finance
Arithmetic Gradients
$$\scriptsize P = A \left[\frac{(1+i)^n-1}{i(1+i)^n}\right] + G \left[\frac{(1+i)^n-in-1}{i^2(1+i)^n}\right]$$
Equivalent Uniform Annual Cost
$$A = P \left[\frac{i(1 + i)^n}{(1 + i)^n - 1}\right]$$
Present and Future Value
$$F = P(1 + i)^n$$