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Kinetic Energy

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$$ E_k = \frac{1}{2}mv^2 $$

Where

  • \(E_k\) is the kinetic energy of the object,
  • \(m\) is the mass of the object, and
  • \(v\) is the velocity of the object.

Sources #

Example #

Kevin throws a 400,000 kg spaceship straight down off of an infinitely tall cliff. After some time, it reaches a terminal velocity of 500 m/s. What is the kinetic energy of the spaceship at this point?

We know that kinetic energy is equal to \(\small \frac{1}{2}mv^2\), so we can plug in the values to get the answer:

$$ \scriptsize E_k = \frac{1}{2}mv^2 \Longrightarrow E_k = \frac{1}{2} \cdot 400000 \cdot 500^2 \Longrightarrow E_k = 5.0 \cdot 10^{10} J $$

See also #